Every house in Delhi will be screen by July 6 as a part of a new plan to check the spread of Coronavirus. Delhi has the second-highest number of COVID19 cases in the country. On Tuesday it recorded the biggest single-day jump of 3947 new infections.
The AAP government says that all houses in the containment zones will be screened by June 30. Delhi has 261 containment zones so far. Surveillance and contact tracing will be strengthened in these neighbourhoods.
With the 3947 new cases reported in the last 24 hours, the total number of cases in Delhi has risen to 66,602. Maharashtra held the previous highest single-day spike record at 3874 in 24 hours on June 20.
A committee chaired by NITI Aayog member DR V.K Paul has made the recommendations based on which the new orders have been passed.
A strict monitoring plan will be implemented at district-level as per the revised strategy. The COVID-19 task forces in districts – that was earlier supervised only by the district magistrates – will have the district commissioner of police, civic body officials, epidemiologists from the MCD (Municipal Corporation of Delhi), and IT professionals to monitor Aarogya Setu app, used by the government for contact-tracing.
The state task force will be headed by the Chief Minister Arvind Kejriwal.
A team of local-level medical officials or Asha workers will visit the households and ask people whether they have been going through any symptoms lately of Coronavirus or they’ve had high fever or cough.
Twenty-thousand samples will be collected as a part of a sero survey, to estimate prevalence of coronavirus in the national capital, which will start on Saturday (June 27). The results will be released on July 10.
The Delhi government has converted two hotels – Ginger Hotel and Tulip Hotel as COVID care centres for healthcare workers in an effort to prevent the frontline workers from contracting the virus.